Cos^2(x)-5cos(x)+4=0

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Solution for Cos^2(x)-5cos(x)+4=0 equation: 


Simplifying
Cos2(x) + -5cos(x) + 4 = 0

Multiply os2C * x
os2xC + -5cos(x) + 4 = 0

Multiply cos * x
os2xC + -5cosx + 4 = 0

Reorder the terms:
4 + -5cosx + os2xC = 0

Solving
4 + -5cosx + os2xC = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -5cosx + -4 + os2xC = 0 + -4

Reorder the terms:
4 + -4 + -5cosx + os2xC = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -5cosx + os2xC = 0 + -4
-5cosx + os2xC = 0 + -4

Combine like terms: 0 + -4 = -4
-5cosx + os2xC = -4

Add '-1os2xC' to each side of the equation.
-5cosx + os2xC + -1os2xC = -4 + -1os2xC

Combine like terms: os2xC + -1os2xC = 0
-5cosx + 0 = -4 + -1os2xC
-5cosx = -4 + -1os2xC

Divide each side by '-5osx'.
c = 0.8o-1s-1x-1 + 0.2sC

Simplifying
c = 0.8o-1s-1x-1 + 0.2sC

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